How much copper can be obtained from 100 g of copper sulphate (CuSO4)? (Atomic mass of Cu = 63.5 u)

Question

How much copper can be obtained from 100 g of copper sulphate (CuSO4)? (Atomic mass of Cu = 63.5 u) (A) 29.81 g (B) 19.81 g (C) 39.81 g (D) 9.8 g

Tardigrade Admin · Accepted Answer

The molar mass of CuSO4 = 63.5 + 32 + 4 × 16 = 159.5 amu or u One mole of CuSO4 contains one mole of Cu. 159.5 g of CuSO4 contains 63.5 g of copper. ∴ 100 g of CuSO4 contains = (63.5/159.5) × 100 = 39.81 g of copper

Q. How much copper can be obtained from $100 g$ of copper sulphate $(C u S O_{4})$ ? (Atomic mass of $C u = 63.5 u$ )

29.81 g

19.81 g

39.81 g

9.8 g

The molar mass of $C u S O_{4} = 63.5 + 32 + 4 \times 16$
$= 159.5$ amu or $u$
One mole of $C u S O_{4}$ contains one mole of $C u$ .
$159.5 g$ of $C u S O_{4}$ contains $63.5 g$ of copper.
$∴ 100 g$ of $C u S O_{4}$ contains
$= \frac{63.5}{159.5} \times 100 = 39.81 g$ of copper

Q. How much copper can be obtained from 100g of copper sulphate (CuSO4​)? (Atomic mass of Cu=63.5u)