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Q.
How much copper can be obtained from $100\, g$ of copper sulphate $(CuSO_4)$? (Atomic mass of $Cu = 63.5 \,u$)
Some Basic Concepts of Chemistry
Solution:
The molar mass of $CuSO_4 = 63.5 + 32 + 4 \times 16$
$= 159.5$ amu or $u$
One mole of $CuSO_4$ contains one mole of $Cu$.
$159.5 \,g$ of $CuSO_4$ contains $63.5 \,g$ of copper.
$\therefore 100\,g $ of $CuSO_4$ contains
$ = \frac{63.5}{159.5} \times 100 = 39.81\,g $ of copper