How many numbers of 6 digits can be formed from the digits of the number 112233 ?

Question

How many numbers of 6 digits can be formed from the digits of the number 112233 ? (A) 30 (B) 60 (C) 90 (D) 120

Tardigrade Admin · Accepted Answer

Here the digits repeat as: 1 = 2 times, 2 = 2 times and 3 = 2 times Thus the total no. of the permutation = (( 2 + 2 + 2)! /2! 2! 2!) = (6 ×5 × 4 × 3 × 2 × 1/2 × 2 × 2) = 90

Q. How many numbers of 6 digits can be formed from the digits of the number 112233 ?

30

60

90

120

Here the digits repeat as:
1 = 2 times, 2 = 2 times and 3 = 2 times
Thus the total no. of the permutation
$= \frac{( 2 + 2 + 2 )!}{2 ! 2 ! 2 !} = \frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{2 \times 2 \times 2} = 90$

Q. How many numbers of 6 digits can be formed from the digits of the number 112233 ?

30

60

90

120

Here the digits repeat as: 1 = 2 times, 2 = 2 times and 3 = 2 times Thus the total no. of the permutation =2!2!2!(2+2+2)!​=2×2×26×5×4×3×2×1​=90

Here the digits repeat as:
1 = 2 times, 2 = 2 times and 3 = 2 times
Thus the total no. of the permutation
$= \frac{( 2 + 2 + 2 )!}{2 ! 2 ! 2 !} = \frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{2 \times 2 \times 2} = 90$