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  4. How many numbers of 6 digits can be formed from the digits of the number 112233 ?

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Q. How many numbers of 6 digits can be formed from the digits of the number 112233 ?

Permutations and Combinations

Solution:

Here the digits repeat as:
1 = 2 times, 2 = 2 times and 3 = 2 times
Thus the total no. of the permutation
$= \frac{( 2 + 2 + 2)! }{2! 2! 2!} = \frac{6 \times5 \times 4 \times 3 \times 2 \times 1}{2 \times 2 \times 2} = 90 $