Question

How many number of moles of nitrogen will be present in $2.24L$ of nitrogen gas at $STP$?

• A. $9.9$
• B. $0.099$
• C. $0.001$
• D. $1.00$

Answer 1

Answer: (B)

$PV=nRT$, $P=1atm$, $T=273K$, $V=2.24L$,
$R=0.0821L$ atm $K^{-1}$ $mo{l}^{-1}$
$n=\frac{1\times 2.24}{0.0821\times 273}$ = $0.099$