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  4. How many number of moles of nitrogen will be present in 2.24 L of nitrogen gas at STP?

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Q. How many number of moles of nitrogen will be present in $2.24\, L$ of nitrogen gas at $STP$?

States of Matter

Solution:

$PV=nRT$, $P=1 \,atm$, $T=273\, K$, $V=2.24 \,L$,
$R=0.0821 \,L$ atm $K^{-1}$ $mol^{-1}$
$n=\frac{1\times2.24}{0.0821\times273}$ = $0.099$