How many moles of iodine are liberated when 1 mole of potassium dichromate reacts with potassium iodide?

Question

How many moles of iodine are liberated when 1 mole of potassium dichromate reacts with potassium iodide? (A) 1 (B) 2 (C) 3 (D) 4

Tardigrade Admin · Accepted Answer

The balanced chemical reaction is 14 H ++ Cr 2 O 72-+6 I - longrightarrow 2 Cr 3++3 I 2+7 H 2 O Thus, 3 mole I 2 is evolved, when KI reacts with 1 mole of potassium dichromate.

Q. How many moles of iodine are liberated when $1$ mole of potassium dichromate reacts with potassium iodide?

1

2

3

4

The balanced chemical reaction is
$14 H^{+} + C r_{2} O_{7}^{2 -} + 6 I^{-} ⟶ 2 C r^{3 +} + 3 I_{2} + 7 H_{2} O$
Thus, $3$ mole $I_{2}$ is evolved, when $K I$ reacts with $1$ mole of potassium dichromate.

Q. How many moles of iodine are liberated when 1 mole of potassium dichromate reacts with potassium iodide?

1

2

3

4

The balanced chemical reaction is 14H++Cr2​O72−​+6I−⟶2Cr3++3I2​+7H2​O Thus, 3 mole I2​ is evolved, when KI reacts with 1 mole of potassium dichromate.

Q. How many moles of iodine are liberated when $1$ mole of potassium dichromate reacts with potassium iodide?

The balanced chemical reaction is
$14 H^{+} + C r_{2} O_{7}^{2 -} + 6 I^{-} ⟶ 2 C r^{3 +} + 3 I_{2} + 7 H_{2} O$
Thus, $3$ mole $I_{2}$ is evolved, when $K I$ reacts with $1$ mole of potassium dichromate.