How many moles of iodine are liberated when 1 mole of potassium dichromate reacts with potassium iodide?

Question

How many moles of iodine are liberated when 1 mole of potassium dichromate reacts with potassium iodide? (A) 1 (B) 2 (C) 3 (D) 4

Tardigrade Admin · Accepted Answer

The balanced chemical reaction is 14 H ++ Cr 2 O 72-+6 I- arrow 2 Cr 3++3 I 2+7 H 2 O Thus; when KI reacts with 1 mole of potassium dichromate, 3 moles of I2 are evolved.

Q. How many moles of iodine are liberated when 1 mole of potassium dichromate reacts with potassium iodide?

1

2

3

4

The balanced chemical reaction is

$14 H^{+} + C r_{2} O_{7}^{2 -} + 6 I^{-} \to 2 C r^{3 +} + 3 I_{2} + 7 H_{2} O$

Thus; when $K I$ reacts with 1 mole of potassium dichromate, 3 moles of $I_{2}$ are evolved.

Q. How many moles of iodine are liberated when 1 mole of potassium dichromate reacts with potassium iodide?

1

2

3

4

The balanced chemical reaction is 14H++Cr2​O72−​+6I−→2Cr3++3I2​+7H2​O Thus; when KI reacts with 1 mole of potassium dichromate, 3 moles of I2​ are evolved.

The balanced chemical reaction is

$14 H^{+} + C r_{2} O_{7}^{2 -} + 6 I^{-} \to 2 C r^{3 +} + 3 I_{2} + 7 H_{2} O$

Thus; when $K I$ reacts with 1 mole of potassium dichromate, 3 moles of $I_{2}$ are evolved.