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Q. How many moles of iodine are liberated when 1 mole of potassium dichromate reacts with potassium iodide?

Redox Reactions

Solution:

The balanced chemical reaction is

$14\, H ^{+}+ Cr _{2} O _{7}^{2-}+6 I^- \rightarrow 2 Cr ^{3+}+3 I _{2}+7 H _{2} O$

Thus; when $KI$ reacts with 1 mole of potassium dichromate, 3 moles of $I_{2}$ are evolved.