How many molecules of HCl gas will be produced by reacting 112 L of H 2(0° C , 1 atm ) with 213 g of Cl 2 ?

Question

How many molecules of HCl gas will be produced by reacting 112 L of H 2(0° C , 1 atm ) with 213 g of Cl 2 ? (A)  3.61 × 1024  (B) 6.13 × 1023  (C)  6.13 × 1024  (D) 1.63 × 1024

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/5d589513c7efb87857881c298b4d89d6-.png" /> Here, Cl 2( g) is limiting reagent, 1 Mole C l2(g) produces H C l(g) =2 × 6.022 × 1023 molecules 3 Moles Cl 2( g ) produces HCl ( g ) =3 × 2 × 6.022 × 1023 molecules =3.61 × 1024 molecules

Q. How many molecules of $H Cl$ gas will be produced by reacting $112 L$ of $H_{2} (0^{\circ} C, 1 a t m)$ with $213 g$ of $C l_{2}$ ?

$3.61 \times 1 0^{24}$

$6.13 \times 1 0^{23}$

$6.13 \times 1 0^{24}$

$1.63 \times 1 0^{24}$

Here, $C l_{2 (g)}$ is limiting reagent,

1 Mole $C l_{2 (g)}$ produces $H C l_{(g)}$

$= 2 \times 6.022 \times 1 0^{23}$ molecules

3 Moles $C l_{2 (g)}$ produces $H C l_{(g)}$

$= 3 \times 2 \times 6.022 \times 1 0^{23}$ molecules

$= 3.61 \times 1 0^{24}$ molecules

Q. How many molecules of HCl gas will be produced by reacting 112L of H2​(0∘C,1atm) with 213g of Cl2​ ?

3.61×1024

6.13×1023

6.13×1024

1.63×1024