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  4. How many molecules of HCl gas will be produced by reacting 112 L of H 2(0° C , 1 atm ) with 213 g of Cl 2 ?

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Q. How many molecules of $HCl$ gas will be produced by reacting $112 \,L$ of $H _{2}\left(0^{\circ} C , 1 atm \right)$ with $213 \,g$ of $Cl _{2}$ ?

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Solution:

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Here, $Cl _{2( g) }$ is limiting reagent,

1 Mole $C l_{2(g)}$ produces $H C l_{(g)}$

$=2 \times 6.022 \times 10^{23}$ molecules

3 Moles $Cl _{2( g )}$ produces $HCl _{( g )}$

$=3 \times 2 \times 6.022 \times 10^{23}$ molecules

$=3.61 \times 10^{24}$ molecules