How many hyperconjugation structures can be drawn for isopropyl cation?

Question

How many hyperconjugation structures can be drawn for isopropyl cation? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

No. of hyperconjugation structures = No. of α-H atoms adjacent to sp 2 hybridised C-atom. As 6 α- H atoms are present in isopropyl cation ( CH 3)2 overset+CH, six hyperconjugation structures can be drawn.

Q. How many hyperconjugation structures can be drawn for isopropyl cation?

No. of hyperconjugation structures $=$ No. of $α$ -H atoms adjacent to $s p^{2}$ hybridised $C$ -atom.
As $6 α - H$ atoms are present in isopropyl cation $(C H_{3})_{2} C + H$ , six hyperconjugation structures can be drawn.

Q. How many hyperconjugation structures can be drawn for isopropyl cation?

No. of hyperconjugation structures = No. of α-H atoms adjacent to sp2 hybridised C-atom. As 6α−H atoms are present in isopropyl cation (CH3​)2​C+H, six hyperconjugation structures can be drawn.

No. of hyperconjugation structures $=$ No. of $α$ -H atoms adjacent to $s p^{2}$ hybridised $C$ -atom.
As $6 α - H$ atoms are present in isopropyl cation $(C H_{3})_{2} C + H$ , six hyperconjugation structures can be drawn.