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Q.
How many hyperconjugation structures can be drawn for isopropyl cation?
Organic Chemistry – Some Basic Principles and Techniques
Solution:
No. of hyperconjugation structures $=$ No. of $\alpha$-H atoms adjacent to $sp ^{2}$ hybridised $C$-atom.
As $6 \alpha- H$ atoms are present in isopropyl cation $\left( CH _{3}\right)_{2} \overset{+}{C}H$, six hyperconjugation structures can be drawn.
