Question

How many hyperconjugation structures can be drawn for isopropyl cation?

Answer 1

Answer: 6

No. of hyperconjugation structures =No. of
$\alpha -H$ atoms adjacent to $s{p}^2$ hybridised $C$-atom. $6a-H$ atoms are present in isopropyl cation ${\left({\left(CH\right)}_3\right)}_2{\left(CH\right)}^{+}$ , six hyperconjugation structures can be drawn.