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Q.
How many hyperconjugation structures can be drawn for isopropyl cation?
NTA AbhyasNTA Abhyas 2022
Solution:
No. of hyperconjugation structures =No. of
$\alpha -H$ atoms adjacent to $sp^{2}$ hybridised $C$-atom. $6a-H$ atoms are present in isopropyl cation $\left(\left(CH\right)_{3}\right)_{2}\left(CH\right)^{+}$ , six hyperconjugation structures can be drawn.
