Question

How many grams of $NaOH$ will be required to neutralize $12.2g$ of benzoic acid

• A. 40 gms
• B. 16 gms
• C. 4 gms
• D. 12.2 gms

Answer 1

Answer: (C)

$C_6{H}_{5}COOH+NaOH\to C_6{H}_{5}COONa+H_{2}O$

$\frac{w}{40}=\frac{12.2}{122}$ or $w=4gm$