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Q. How many grams of $NaOH$ will be required to neutralize $12.2\, g$ of benzoic acid

Solutions

Solution:

$C_6H_5COOH + NaOH \rightarrow C_6H_5COONa + H_2O$

$\frac{w}{40} = \frac{12.2}{122}$ or $w = 4\,gm$