How many grams of NaOH should be added to water to prepare 250 ml solution of 2 M NaOH ?

Question

How many grams of NaOH should be added to water to prepare 250 ml solution of 2 M NaOH ? (A) 9.6 × 103 (B) 2.4 × 103 (C) 20 (D) 24

Tardigrade Admin · Accepted Answer

Moles of NaOH =( M × V ( mL )/1000) =(2 × 250/1000)=0.5 moles of NaOH Moles =( text given mass / text mol. mass ) ∴ 0.5 mole =(x/40) given mass =40 × 0.5=20 g

Q. How many grams of $N a O H$ should be added to water to prepare $250 m l$ solution of $2 M N a O H$ ?

$9.6 \times 1 0^{3}$

$2.4 \times 1 0^{3}$

20

24

Moles of $N a O H = \frac{M \times V ( m L )}{1000}$
$= \frac{2 \times 250}{1000} = 0.5$ moles of $N a O H$
Moles $= \frac{given mass}{mol. mass}$
$∴ 0.5$ mole $= \frac{x}{40}$
given mass $= 40 \times 0.5 = 20 g$

Q. How many grams of NaOH should be added to water to prepare 250ml solution of 2MNaOH ?

9.6×103

2.4×103

20

24

Moles of NaOH=1000M×V(mL)​ =10002×250​=0.5 moles of NaOH Moles = mol. mass given mass ​ ∴0.5 mole =40x​ given mass =40×0.5=20g

Q. How many grams of $N a O H$ should be added to water to prepare $250 m l$ solution of $2 M N a O H$ ?

$9.6 \times 1 0^{3}$

$2.4 \times 1 0^{3}$

Moles of $N a O H = \frac{M \times V ( m L )}{1000}$
$= \frac{2 \times 250}{1000} = 0.5$ moles of $N a O H$
Moles $= \frac{given mass}{mol. mass}$
$∴ 0.5$ mole $= \frac{x}{40}$
given mass $= 40 \times 0.5 = 20 g$