How many grams of CH3OH should be added to water to prepare 150 mL solution of 2 M CH3OH?

Question

How many grams of CH3OH should be added to water to prepare 150 mL solution of 2 M CH3OH? (A) 9.6 x 103 (B) 2.4 x 103 (C) 9.6 (D) 2.4

Tardigrade Admin · Accepted Answer

Given: 150 ml of 2.0 M CH 3 OH is to be prepared. Number of moles = M × V olume operatornamein L= 2 . 0 × 0 . 1 5 0 = 0 . 3 Molar mass of C H 3 OH = 3 2 . 0 4 g / m o l ∴ Weight of CH 3 OH to be added = 3 2 . 0 4 × 0 . 3 = 9 . 6 1 g

Q. How many grams of CH₃OH should be added to water to prepare 150 mL solution of 2 M CH₃OH?

9.6 x 10³

2.4 x 10³

9.6

2.4

Given: $150 m l$ of $2.0 MC H_{3} O H$ is to be prepared.

Number of moles $= M \times V$ olume $inL = 2.0 \times 0.150 = 0.3$

Molar mass of $C H_{3} O H = 32.04 g / m o l$

$∴$ Weight of $C H_{3} O H$ to be added $= 32.04 \times 0.3 = 9.61 g$

Q. How many grams of CH3OH should be added to water to prepare 150 mL solution of 2 M CH3OH?

9.6 x 103

2.4 x 103

9.6

2.4

Given: 150ml of 2.0MCH3​OH is to be prepared. Number of moles =M×V olume inL=2.0×0.150=0.3 Molar mass of CH3​OH=32.04g/mol ∴ Weight of CH3​OH to be added =32.04×0.3=9.61g

Q. How many grams of CH₃OH should be added to water to prepare 150 mL solution of 2 M CH₃OH?

9.6 x 10³

2.4 x 10³

Given: $150 m l$ of $2.0 MC H_{3} O H$ is to be prepared.

Number of moles $= M \times V$ olume $inL = 2.0 \times 0.150 = 0.3$

Molar mass of $C H_{3} O H = 32.04 g / m o l$

$∴$ Weight of $C H_{3} O H$ to be added $= 32.04 \times 0.3 = 9.61 g$