Question

How many grams of bromine will react with $21g$ of $C_3{H}_6$?

• A. $320$
• B. $160$
• C. $240$
• D. $80$

Answer 1

Answer: (D)

$\because 42g$of propene reacts with $160g$ of bromine.
$\therefore 21g$ of propene $=\frac{160}{12}\times 21=80g$