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Q. How many grams of bromine will react with $21 \,g$ of $C_3H_6$?

Hydrocarbons

Solution:

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$\because 42\,g$of propene reacts with $160\,g$ of bromine.
$\therefore 21\,g$ of propene $ =\frac{160}{12} \times 21 = 80\,g$