Tardigrade
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Tardigrade
Question
Chemistry
How many geometrical isomers are there for [Co (NH3)2Cl4]- (octahedral) and [AuCl2Br2] (square planar)?
Q. How many geometrical isomers are there for
[
C
o
(
N
H
3
)
2
C
l
4
]
−
(octahedral) and
[
A
u
C
l
2
B
r
2
]
(square planar)?
3655
222
Coordination Compounds
Report Error
A
Two cis and trans, no geometrical isomers
21%
B
Two cis and trans, two cis and trans
60%
C
No geometrical isomers, two cis and trans
14%
D
No geometrical isomers, no geometrical isomers
4%
Solution:
[
C
o
(
N
H
3
)
2
C
l
4
]
−
[
A
u
C
l
2
B
r
2
]
−
