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  4. How many geometrical isomers are there for [Co (NH3)2Cl4]- (octahedral) and [AuCl2Br2] (square planar)?

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Q. How many geometrical isomers are there for $[Co (NH_{3})_{2}Cl_{4}]^{-}$ (octahedral) and $[AuCl_{2}Br_{2}]$ (square planar)?

Coordination Compounds

Solution:

$[Co (NH_{3})_{2}Cl_{4}]^{-}$
$ [AuCl_{2}Br_{2}]^{-}$
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