How long would it take to deposit 50 g of Al from an electrolytic cell containing Al2O3 using a current of 105 ampere?

Question

How long would it take to deposit 50 g of Al from an electrolytic cell containing Al2O3 using a current of 105 ampere? (A) 1.54 h (B) 1.42 h (C) 1.32 h (D) 2.15 h

Tardigrade Admin · Accepted Answer

Al3++3e- → Al; Eq. wt. of Al=(27/3)=9 W=Z× I× t ⇒ Z=(Eq. wt./96500) t=(W×96500/Eq. wt.× I) =(50×96500/9×105) =5105.82 s or 1.42 h

Q. How long would it take to deposit $50 g$ of $A l$ from an electrolytic cell containing $A l_{2} O_{3}$ using a current of $105$ ampere?

$1.54 h$

$1.42 h$

$1.32 h$

$2.15 h$

$A l^{3 +} + 3 e^{-} \to A l$ ; Eq. wt. of $A l = \frac{27}{3} = 9$
$W = Z \times I \times t$
$\Rightarrow Z = \frac{Eq . wt .}{96500}$
$t = \frac{W \times 96500}{Eq . wt . \times I}$
$= \frac{50 \times 96500}{9 \times 105}$
$= 5105.82 s$ or $1.42 h$

Q. How long would it take to deposit 50g of Al from an electrolytic cell containing Al2​O3​ using a current of 105 ampere?

1.54h

1.42h

1.32h

2.15h