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Q. How long would it take to deposit $50 \,g$ of $Al$ from an electrolytic cell containing $Al_2O_3$ using a current of $105$ ampere?

Electrochemistry

Solution:

$Al^{3+}+3e^{-} \to Al$; Eq. wt. of $Al=\frac{27}{3}=9$
$W=Z\times I\times t$
$\Rightarrow Z=\frac{Eq. wt.}{96500}$
$t=\frac{W\times96500}{Eq. wt.\times I}$
$=\frac{50\times96500}{9\times105}$
$=5105.82\,s$ or $1.42\,h$