HNO3 oxidises NH+4 ions to nitrogen and itself gets reduced to NO2 The moles of HNO3 required by 1 mol of (NH4)2SO4 is

Question

HNO3 oxidises NH+4 ions to nitrogen and itself gets reduced to NO2 The moles of HNO3 required by 1 mol of (NH4)2SO4 is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/74a15788a67ba3c4a425b7d024a42194-.png" /> ∴ 6HNO3+NH+4 → N2+NO2 Thus for 1 mole of NH+4, we require 6 moles of HNO3

Q. $H N O_{3}$ oxidises $N H_{4}^{+}$ ions to nitrogen and itself gets reduced to $N O_{2}$ The moles of $H N O_{3}$ required by $1 m o l$ of $(N H_{4})_{2} S O_{4}$ is

$∴ 6 H N O_{3} + N H_{4}^{+} \to N_{2} + N O_{2}$
Thus for $1$ mole of $N H_{4}^{+}$ , we require $6$ moles of $H N O_{3}$

Q. HNO3​ oxidises NH4+​ ions to nitrogen and itself gets reduced to NO2​ The moles of HNO3​ required by 1mol of (NH4​)2​SO4​ is

∴6HNO3​+NH4+​→N2​+NO2​ Thus for 1 mole of NH4+​, we require 6 moles of HNO3​

Q. $H N O_{3}$ oxidises $N H_{4}^{+}$ ions to nitrogen and itself gets reduced to $N O_{2}$ The moles of $H N O_{3}$ required by $1 m o l$ of $(N H_{4})_{2} S O_{4}$ is

$∴ 6 H N O_{3} + N H_{4}^{+} \to N_{2} + N O_{2}$
Thus for $1$ mole of $N H_{4}^{+}$ , we require $6$ moles of $H N O_{3}$