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  4. HNO3 oxidises NH+4 ions to nitrogen and itself gets reduced to NO2 The moles of HNO3 required by 1 mol of (NH4)2SO4 is

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Q. $HNO_{3}$ oxidises $NH^{+}_{4}$ ions to nitrogen and itself gets reduced to $NO_{2}$ The moles of $HNO_{3}$ required by $1\,mol$ of $(NH_{4})_{2}SO_{4}$ is

Redox Reactions

Solution:

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$\therefore 6HNO_{3}+NH^{+}_{4} \to N_{2}+NO_{2}$
Thus for $1$ mole of $NH^{+}_{4}$, we require $6$ moles of $HNO_{3}$