Question

Highest oxidation state of $Mn$ is present in

• A. $KMn{O}_4$
• B. $K_{2}Mn{O}_4$
• C. $M{n}_2{O}_3$
• D. $Mn{O}_2$

Answer 1

Answer: (A)

Let the oxidation state of $Mn$ is $x$.
(a) $KMn{O}_4+1+x+(-2)\times 4=0$
$x-7=0$
$x=+7$
(b) $K_{2}Mn{O}_4(+1)\times 2+x+(-2)\times 4=0$
$x-6=0$
$x=+6$
(c) $M{n}_2{O}_{3}x\times 2+(-2)\times 3=0$
$2x=+6$
$x=+3$
(d) $Mn{O}_{2}x+(-2)\times 2=0$
$x=+4$
Thus, oxidation state of $Mn$ is highest in $KMn{O}_4$.