Highest oxidation state of manganese in fluorides is +4 (MnF4) but highest oxidation state in oxides is +7 (Mn2O7) because

Question

Highest oxidation state of manganese in fluorides is +4 (MnF4) but highest oxidation state in oxides is +7 (Mn2O7) because (A) fluorine is more electronegative than oxygen (B) fluorine does not possess d-orbitals (C) fluorine stabilises lower oxidation state (D) in covalent compounds, fluorine can form single bond only while oxygen forms double bond

Tardigrade Admin · Accepted Answer

Oxygen can form pπ-pπ bonding while fluorine can form only single bonds.

Q. Highest oxidation state of manganese in fluorides is $+ 4 (M n F_{4})$ but highest oxidation state in oxides is $+ 7 (M n_{2} O_{7})$ because

fluorine is more electronegative than oxygen

fluorine does not possess $d$ -orbitals

fluorine stabilises lower oxidation state

in covalent compounds, fluorine can form single bond only while oxygen forms double bond

Oxygen can form $p π - p π$ bonding while fluorine can form only single bonds.

Q. Highest oxidation state of manganese in fluorides is +4(MnF4​) but highest oxidation state in oxides is +7(Mn2​O7​) because