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Chemistry
Highest oxidation state of manganese in fluorides is +4 (MnF4) but highest oxidation state in oxides is +7 (Mn2O7) because
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Q. Highest oxidation state of manganese in fluorides is $+4 (MnF_4)$ but highest oxidation state in oxides is $+7 (Mn_2O_7)$ because
The d-and f-Block Elements
A
fluorine is more electronegative than oxygen
25%
B
fluorine does not possess $d$-orbitals
23%
C
fluorine stabilises lower oxidation state
14%
D
in covalent compounds, fluorine can form single bond only while oxygen forms double bond
37%
Solution:
Oxygen can form $p\pi-p\pi$ bonding while fluorine can form only single bonds.