Question

Hexafluorocobaltate (III) ion is a high spin complex. The hybrid state of cobalt is

• A. $d^{2}s{p}^3$
• B. $s{p}^3{d}^2$
• C. $ds{p}^2$
• D. $s{p}^{3}d.$

Answer 1

Answer: (B)

The formula of the ion is $[Co{F}_6{]}^{3^{-}}$. It is an octahedral complex with high spin. As such the hybrid stste sholuld be $s{p}^3{d}^2$