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Chemistry
Hexafluorocobaltate (III) ion is a high spin complex. The hybrid state of cobalt is
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Q. Hexafluorocobaltate (III) ion is a high spin complex. The hybrid state of cobalt is
Coordination Compounds
A
$d^2sp^3$
10%
B
$sp^3d^2$
54%
C
$dsp^2$
23%
D
$sp^3d.$
12%
Solution:
The formula of the ion is $[CoF_6]^{3^-}$. It is an octahedral complex with high spin. As such the hybrid stste sholuld be $sp^3d^2$