Heat of combustion of glucose is -72 kcal/mol then calculate the required heat during formation of 1.6 gm glucose from CO2 and H2O :-

Question

Heat of combustion of glucose is -72 kcal/mol then calculate the required heat during formation of 1.6 gm glucose from CO2 and H2O :- (A) 0.64 kcal (B) 0.32 kcal (C) 1.028 kcal (D) 2.8 kcal

Tardigrade Admin · Accepted Answer

Mole of Glucose =(1 . 6/180)=0.0088 6CO2+6H2O arrow C6H12O6+6O2 Heat required =0.0088× 72=0.64 kcal

Q. Heat of combustion of glucose is $- 72 k c a l / m o l$ then calculate the required heat during formation of $1.6 g m$ glucose from $C O_{2}$ and $H_{2} O$ :-

$0.64 k c a l$

$0.32 k c a l$

$1.028 k c a l$

$2.8 k c a l$

Mole of Glucose $= \frac{1.6}{180} = 0.0088$
$6 C O_{2} + 6 H_{2} O \to C_{6} H_{12} O_{6} + 6 O_{2}$
Heat required $= 0.0088 \times 72 = 0.64 k c a l$

Q. Heat of combustion of glucose is −72kcal/mol then calculate the required heat during formation of 1.6gm glucose from CO2​ and H2​O :-

0.64kcal

0.32kcal

1.028kcal

2.8kcal