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Q. Heat of combustion of glucose is $-72\,kcal/mol$ then calculate the required heat during formation of $1.6\,gm$ glucose from $CO_{2}$ and $H_{2}O$ :-

NTA AbhyasNTA Abhyas 2022

Solution:

Mole of Glucose $=\frac{1 . 6}{180}=0.0088$
$6CO_{2}+6H_{2}O \rightarrow C_{6}H_{12}O_{6}+6O_{2}$
Heat required $=0.0088\times 72=0.64\,kcal$