HCOOH and CH 3 COOH solution have equal pH. If K1 / K2 (ratio of acid ionization constant) is 4 , their molar concentration ratio will be:

Question

HCOOH and CH 3 COOH solution have equal pH. If K1 / K2 (ratio of acid ionization constant) is 4 , their molar concentration ratio will be: (A) 2 (B) 0.5 (C) 4 (D) 0.25

Tardigrade Admin · Accepted Answer

Equal pH means [ H +]1=[ H +]2 √K1 C1=√K2 C2 (By Ostwaldâs dilution law) or K1 C1=K2 C2 ∴ (C1/C2)=(K2/K1)=(1/4)=0.25

Q. $H COO H$ and $C H_{3} COO H$ solution have equal $p H$ . If $K_{1} / K_{2}$ (ratio of acid ionization constant) is $4$ , their molar concentration ratio will be:

2

0.5

4

0.25

Equal $p H$ means
$[H^{+}]_{1} = [H^{+}]_{2}$
$K_{1} C_{1} = K_{2} C_{2}$
(By Ostwald’s dilution law)
or $K_{1} C_{1} = K_{2} C_{2}$
$∴ \frac{C _{1}}{C _{2}} = \frac{K _{2}}{K _{1}} = \frac{1}{4} = 0.25$

Q. HCOOH and CH3​COOH solution have equal pH. If K1​/K2​ (ratio of acid ionization constant) is 4 , their molar concentration ratio will be:

2

0.5

4

0.25

Equal pH means [H+]1​=[H+]2​ K1​C1​​=K2​C2​​ (By Ostwald’s dilution law) or K1​C1​=K2​C2​ ∴C2​C1​​=K1​K2​​=41​=0.25

Q. $H COO H$ and $C H_{3} COO H$ solution have equal $p H$ . If $K_{1} / K_{2}$ (ratio of acid ionization constant) is $4$ , their molar concentration ratio will be:

Equal $p H$ means
$[H^{+}]_{1} = [H^{+}]_{2}$
$K_{1} C_{1} = K_{2} C_{2}$
(By Ostwald’s dilution law)
or $K_{1} C_{1} = K_{2} C_{2}$
$∴ \frac{C _{1}}{C _{2}} = \frac{K _{2}}{K _{1}} = \frac{1}{4} = 0.25$