1. Tardigrade
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  3. Chemistry
  4. HCOOH and CH 3 COOH solution have equal pH. If K1 / K2 (ratio of acid ionization constant) is 4 , their molar concentration ratio will be:

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Q. $HCOOH$ and $CH _{3} COOH$ solution have equal $pH$. If $K_{1} / K_{2}$ (ratio of acid ionization constant) is $4$ , their molar concentration ratio will be:

Equilibrium

Solution:

Equal $pH$ means
${\left[ H ^{+}\right]_{1}=\left[ H ^{+}\right]_{2}} $
$\sqrt{K_{1} C_{1}}=\sqrt{K_{2} C_{2}} $
(By Ostwald’s dilution law)
or $K_{1} C_{1}=K_{2} C_{2} $
$\therefore \frac{C_{1}}{C_{2}}=\frac{K_{2}}{K_{1}}=\frac{1}{4}=0.25$