H-O-H bond angle in H2O is 104.5° and not 109°28' because of

Question

H-O-H bond angle in H2O is 104.5° and not 109°28' because of (A) lone pair-lone pair repulsion (B) lone pair-bond pair repulsion (C) bond pair-bond pair repulsion (D) high electronegativity of oxygen

Tardigrade Admin · Accepted Answer

The hybridisation of oxygen in water molecule is s p3. So, water molecule must be tetrahedral and have bond angle 109° 28 prime. But due to the presence of two lone pair of electrons on oxygen atom (repulsion between lone pair-lone pair) the bond angle decreases about 104.5° and the geometry becomes distorted tetrahedral or V shaped.

Q. H−O−H bond angle in H2​O is 104.5∘ and not 109∘28′ because of

lone pair-lone pair repulsion

lone pair-bond pair repulsion

bond pair-bond pair repulsion

high electronegativity of oxygen

Q. $H - O - H$ bond angle in $H_{2} O$ is $104. 5^{\circ}$ and not $10 9^{\circ} 2 8^{'}$ because of