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  4. H-O-H bond angle in H2O is 104.5° and not 109°28' because of

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Q. $ H-O-H $ bond angle in $ {{H}_{2}}O $ is $104.5^{\circ} $ and not $109^{\circ}28'$ because of

Chhattisgarh PMTChhattisgarh PMT 2008

Solution:

The hybridisation of oxygen in water molecule is $s p^{3}$. So, water molecule must be tetrahedral and have bond angle $109^{\circ} 28^{\prime}$. But due to the presence of two lone pair of electrons on oxygen atom (repulsion between lone pair-lone pair) the bond angle decreases about $104.5^{\circ}$ and the geometry becomes distorted tetrahedral or $V$ shaped.