H 3 PO 4 can be neutralized by NaOH , Ca ( OH )2 and Al ( OH )3. 1equivalent of H 3 PO 4 will require mole of each in the ratio

Question

H 3 PO 4 can be neutralized by NaOH , Ca ( OH )2 and Al ( OH )3. 1equivalent of H 3 PO 4 will require mole of each in the ratio (A) 1: 1: 1 (B) 1: 0.5: 0.33 (C) 1: 2: 3 (D) 2: 3: 6

Tardigrade Admin · Accepted Answer

H 3 PO 4 (1 equivalent) ≡ 1 equivalent NaOH ≡ 1 equivalent Ca ( OH )2 ≡ 1 equivalnet Al ( OH )3 In terms of moles 1 equivalent NaOH ≡ 1 mol NaOH 1 equivalent Ca ( OH )2=0.5 mol Ca ( OH )2 1 equivalent Al ( OH )3 ≡ (1/3) mol Al ( OH )3 Thus, molar ratio is 1: (1/2): (1/3)

Q. $H_{3} P O_{4}$ can be neutralized by $N a O H, C a (O H)_{2}$ and $A l (O H)_{3}$ . 1equivalent of $H_{3} P O_{4}$ will require mole of each in the ratio

$1 : 1 : 1$

$1 : 0.5 : 0.33$

$1 : 2 : 3$

$2 : 3 : 6$

Q. H3​PO4​ can be neutralized by NaOH,Ca(OH)2​ and Al(OH)3​. 1equivalent of H3​PO4​ will require mole of each in the ratio

1:1:1

1:0.5:0.33

1:2:3

2:3:6

H3​PO4​ (1 equivalent) ≡1 equivalent NaOH ≡1 equivalent Ca(OH)2​ ≡1 equivalnet Al(OH)3​ In terms of moles 1 equivalent NaOH≡1 mol NaOH 1 equivalent Ca(OH)2​=0.5molCa(OH)2​ 1 equivalent Al(OH)3​≡31​molAl(OH)3​ Thus, molar ratio is 1:21​:31​

Q. $H_{3} P O_{4}$ can be neutralized by $N a O H, C a (O H)_{2}$ and $A l (O H)_{3}$ . 1equivalent of $H_{3} P O_{4}$ will require mole of each in the ratio

$1 : 1 : 1$

$1 : 0.5 : 0.33$

$1 : 2 : 3$

$2 : 3 : 6$