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Q. $H _3 PO _4$ can be neutralized by $NaOH , Ca ( OH )_2$ and $Al ( OH )_3$. 1equivalent of $H _3 PO _4$ will require mole of each in the ratio

General Principles and Processes of Isolation of Elements

Solution:

$H _3 PO _4$ (1 equivalent) $\equiv 1$ equivalent $NaOH$
$\equiv 1$ equivalent $Ca ( OH )_2$
$\equiv 1$ equivalnet $Al ( OH )_3$
In terms of moles
$1$ equivalent $NaOH \equiv 1$ mol $NaOH$
$1$ equivalent $Ca ( OH )_2=0.5 mol Ca ( OH )_2$
$1$ equivalent $Al ( OH )_3 \equiv \frac{1}{3} mol Al ( OH )_3$
Thus, molar ratio is $1: \frac{1}{2}: \frac{1}{3}$