Question

$H_{2}O$ is dipolar, whereas $Be{F}_2$ is not. It is because

• A. the electronegativity of $F$ is greater than that of $O$
• B. $H_{2}O$ involves hydrogen bonding whereas $Be{F}_2$ is a discrete molecule
• C. $H_{2}O$ is linear and $Be{F}_2$ is angular
• D. $H_{2}O$ is angular and $Be{F}_2$ is linear

Answer 1

Answer: (D)

The structure of $H_{2}O$ is angular or $V$-shape and has $s{p}^3$-hybridisation and $104.5^{\circ }$ bond angle. Thus, its dipole moment is positive or more than zero.

But in $Be{F}_2$, structure is linear due to $sp$ hybridisation $(\mu =0)$

Thus, due to $\mu >0,H_{2}O$ is dipolar and due to $\mu =0$, $Be{F}_2$ is non-polar.