Question

$ {{H}_{2}}O $ is dipolar, whereas $ Be{{F}_{2}} $ is not. It is because

• A. the electronegativity of $F$ is greater than that of $O$
• B. $ {{H}_{2}}O $ involves hydrogen bonding whereas $ Be{{F}_{2}} $ is a discrete molecule
• C. $ {{H}_{2}}O $ is linear and $ Be{{F}_{2}} $ is angular
• D. $ {{H}_{2}}O $ is angular and $ Be{{F}_{2}} $ is linear

Answer 1

Answer: (D)

The structure of $H _{2} O$ is angular or $V$-shape and has $s p^{3}$-hybridisation and $104.5^{\circ}$ bond angle. Thus, its dipole moment is positive or more than zero.

But in $BeF _{2}$, structure is linear due to $s p$ hybridisation $(\mu=0)$

Thus, due to $\mu>0, H _{2} O$ is dipolar and due to $\mu=0$, $BeF _{2}$ is non-polar.