H2 evolved at STP on complete reaction of 27 g of aluminium with excess of aqueous NaOH would be

Question

H2 evolved at STP on complete reaction of 27 g of aluminium with excess of aqueous NaOH would be (A) 22.4 litres (B) 44.8 litres (C) 67.2 litres (D) 33.6 litres

Tardigrade Admin · Accepted Answer

H2O + underset27 gAl + NaOH → NaAlO2 + underset(3/2) × 22.4 = 33.6 L (3/2) H2

Q. $H_{2}$ evolved at $STP$ on complete reaction of $27 g$ of aluminium with excess of aqueous $N a O H$ would be

$22.4$ litres

$44.8$ litres

$67.2$ litres

$33.6$ litres

$H_{2} O + 27 g A l + N a O H \to N a A l O_{2} + \frac{3}{2} \times 22.4 = 33.6 L \frac{3}{2} H_{2}$

Q. H2​ evolved at STP on complete reaction of 27g of aluminium with excess of aqueous NaOH would be

22.4 litres

44.8 litres

67.2 litres

33.6 litres