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Q. $H_2$ evolved at $STP$ on complete reaction of $27\, g$ of aluminium with excess of aqueous $NaOH$ would be

Some Basic Concepts of Chemistry

Solution:

$H_2O + \underset{27\,g}{Al} + NaOH \to NaAlO_2 + \underset{\frac{3}{2} \times 22.4 = 33.6\,L}{ \frac{3}{2} H_2}$