Question

Green light wavelength 5460 $\mathring{A}$ is incident on an
air-glass interface. If the refractive index of glass
is 1.5, the wavelength of light in glass would be
$(c=3\times {10}^{8}m{s}^{-1})$

• A. 3640 $\mathring{A}$
• B. 5460 $\mathring{A}$
• C. 4861 $\mathring{A}$
• D. none of these

Answer 1

Answer: (A)

${\lambda }_g=\frac{{\lambda }_a}{\mu }=\frac{5460}{1.5}=3640\mathring{A}$