Question

Green light wavelength 5460 $ \mathring{A}$ is incident on an
air-glass interface. If the refractive index of glass
is 1.5, the wavelength of light in glass would be
$ ( c= 3 \times {10}^8 m s^{-1} ) $

• A. 3640 $ \mathring{A}$
• B. 5460 $ \mathring{A}$
• C. 4861 $ \mathring{A}$
• D. none of these

Answer 1

Answer: (A)

$ {\lambda }_g = \frac{{\lambda }_a}{ \mu } = \frac{ 5460 }{1.5} = 3640 \mathring{A}$