Gravitational potential V versus distance r graph is represented in the figure. The magnitude of gravitational field intensity is equal to

Question

Gravitational potential V versus distance r graph is represented in the figure. The magnitude of gravitational field intensity is equal to <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-0nyklrsqhikqs8uz.jpg" /> (A) 8NKg- 1 (B) 4NKg- 1 (C) 6NKg- 1 (D) 2NKg- 1

Tardigrade Admin · Accepted Answer

| overset arrow E|=(Δ V/Δ r)=(8 - 4/(1) sin (30)o)=8Nkg- 1

Q. Gravitational potential $V$ versus distance $r$ graph is represented in the figure. The magnitude of gravitational field intensity is equal to

$8 N K g^{- 1}$

$4 N K g^{- 1}$

$6 N K g^{- 1}$

$2 N K g^{- 1}$

$∣ ∣ E \to ∣ ∣ = \frac{Δ V}{Δ r} = \frac{8 - 4}{( 1 ) s in ( 30 ) ^{o}} = 8 N k g^{- 1}$

Q. Gravitational potential V versus distance r graph is represented in the figure. The magnitude of gravitational field intensity is equal to

8NKg−1

4NKg−1

6NKg−1

2NKg−1