Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Gravitational potential $V$ versus distance $r$ graph is represented in the figure. The magnitude of gravitational field intensity is equal to
Question

NTA AbhyasNTA Abhyas 2022

Solution:

$\left|\overset{ \rightarrow }{E}\right|=\frac{\Delta V}{\Delta r}=\frac{8 - 4}{\left(1\right) sin \left(30\right)^{o}}=8Nkg^{- 1}$