Graph between the square of the velocity (v) of a particle and the distance (s) moved is shown in figure. The acceleration of the particle in kilometers per hour square is :

Question

Graph between the square of the velocity (v) of a particle and the distance (s) moved is shown in figure. The acceleration of the particle in kilometers per hour square is : (A) 2250 (B) 3084 (C) - 2250 (D) - 3084

Tardigrade Admin · Accepted Answer

v2 =u2+2 a s a =(v2-u2/2 s)=((900)-(4600)/2 × 0.6)=-(3700/1.2) =-3084 km / hr 2

Q. Graph between the square of the velocity $(v)$ of a particle and the distance $(s)$ moved is shown in figure. The acceleration of the particle in kilometers per hour square is :

2250

3084

- 2250

- 3084

$v^{2} = u^{2} + 2 a s$
$a = \frac{v ^{2} - u ^{2}}{2 s} = \frac{( 900 ) - ( 4600 )}{2 \times 0.6} = - \frac{3700}{1.2}$
$= - 3084 km / h r^{2}$

Q. Graph between the square of the velocity (v) of a particle and the distance (s) moved is shown in figure. The acceleration of the particle in kilometers per hour square is :