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Q. Graph between the square of the velocity $(v)$ of a particle and the distance $(s)$ moved is shown in figure. The acceleration of the particle in kilometers per hour square is :Physics Question Image

Motion in a Straight Line

Solution:

$v^{2} =u^{2}+2 a s$
$a =\frac{v^{2}-u^{2}}{2 s}=\frac{(900)-(4600)}{2 \times 0.6}=-\frac{3700}{1.2}$
$=-3084\, km / hr ^{2}$